JEE Class main Answered
solve the question below
Asked by sarveshvibrantacademy | 21 Mar, 2019, 03:45: PM
Expert Answer
maximum value of cos-1(x) = π .
Hence if cos-1(a) + cos-1(b) + cos-1(c) = 3π, then cos-1(a) = cos-1(b) = cos-1(c) = π
hence a = b = c = -1 .............................(1)
Given f(1) = 2 and f(x+y) = f(x) f(y) for all x,y
f(2) = f(1+1) = f(1) f(1) = 2×2 = 4
f(3) = f(1+2) = f(1) f(2) = 2×4 = 8
a2f(1) + b2f(2) + c2f(3) +[ (a+b+c) / ( a2f(1) + b2f(2) + c2f(3) ) ] = a4 + b8 + c16 + [ (a+b+c) / ( a4 + b8 + c16 ) ] ..................(2)
substituting values of a, b and c from (1) in eqn.(2), we get, 1+1+1+[ (-3) / (1+1+1) ] = 2
Answered by Thiyagarajan K | 21 Mar, 2019, 05:51: PM
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