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solve the below question

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Asked by sarveshvibrantacademy 22nd March 2019, 3:35 PM
Answered by Expert
Answer:
begin mathsize 16px style cos to the power of negative 1 end exponent square root of fraction numerator 1 plus cosx over denominator 2 end fraction end root
equals cos to the power of negative 1 end exponent square root of fraction numerator 2 cos squared space begin display style straight x over 2 end style over denominator 2 end fraction end root space space space space space space space space space space space 1 plus cosx equals 2 cos squared space straight x divided by 2
equals cos to the power of negative 1 end exponent open parentheses cos straight x over 2 close parentheses
equals straight x over 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space cos to the power of negative 1 end exponent left parenthesis cosx right parenthesis equals straight x space end style
Answered by Expert 22nd March 2019, 4:45 PM
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