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tan tita+sec tita -1/tan tita-sec tita+1
Asked by gopuradhika1128 | 28 Jul, 2021, 20:45: PM
answered-by-expert Expert Answer
Q: Prove that: (tan theta + sec theta - 1)/(tan theta - sec theta + 1) = cos theta/1 + sin theta

fraction numerator tanθ plus secθ minus 1 over denominator tanθ minus secθ plus 1 end fraction equals fraction numerator tanθ plus secθ minus open parentheses sec squared straight theta minus tan squared straight theta close parentheses over denominator tanθ minus secθ plus 1 end fraction equals fraction numerator tanθ plus secθ minus open parentheses secθ minus tanθ close parentheses open parentheses secθ plus tanθ close parentheses over denominator tanθ minus secθ plus 1 end fraction equals fraction numerator open parentheses 1 minus secθ plus tanθ close parentheses open parentheses secθ plus tanθ close parentheses over denominator tanθ minus secθ plus 1 end fraction equals open parentheses secθ plus tanθ close parentheses equals 1 over cosθ plus sinθ over cosθ equals fraction numerator 1 plus sinθ over denominator cosθ end fraction
Answered by Renu Varma | 04 Aug, 2021, 12:18: PM
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