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Asked by adjacentcalliber10 | 25 May, 2019, 08:48: PM
answered-by-expert Expert Answer
y equals e to the power of a x plus b end exponent rightwards double arrow y subscript 1 equals fraction numerator d y over denominator d x end fraction equals e to the power of a x plus b end exponent space fraction numerator d over denominator d x end fraction left parenthesis a x plus b right parenthesis equals a space e to the power of a x plus b end exponent rightwards double arrow y subscript 2 equals fraction numerator d squared y over denominator d x squared end fraction equals a squared e to the power of a x plus b end exponent space rightwards double arrow left parenthesis y subscript 2 right parenthesis subscript 0 equals right enclose fraction numerator d squared y over denominator d x squared end fraction end enclose subscript x equals 0 end subscript equals a squared e to the power of a left parenthesis 0 right parenthesis plus b end exponent space equals a squared e to the power of b space
Answered by Renu Varma | 27 May, 2019, 10:19: AM

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JEE main - Maths
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