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NEET Class neet Answered

Solutions 2, 3,&4 please sir ,q.n 3 nhi ban raha hai 
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Asked by brijk456 | 31 Jul, 2019, 10:14: AM
answered-by-expert Expert Answer
Let the reference direction for all the forces be X-axis of cartesian coord system.
Vectors of all the three forces are drawn in figure.
 
Let i, j are unit vectors along the X-axis and Y-axis respectively
 
F1 = 300 i   ;   F2 = 200√3 i + 200 j  ;  F3 = -200√3 i + 200 j
 
Resultant F1+ F2 +F3 = 300 i + 400 j 
 
Magnitude of resultant force = begin mathsize 12px style square root of 300 squared space plus space 400 squared end root space equals space 500 space N end style  ; direction = sin-1 (400/300) = 53°
 
Hence resultant of the given three forces is 500 N at 53°
Answered by Thiyagarajan K | 31 Jul, 2019, 11:57: AM
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