Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days


Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number


Mon to Sat - 11 AM to 8 PM

CBSE - XII Science - Chemistry - Coordination Compounds

Sir, Please give me a detailed description of why the d-orbitals split when the negative field due to ligands surrounds the metal atom/ion? How does it become assymetrical? Please give detailed explanation of the very same.

Asked by Ishita Puranik 25th December 2011, 12:50 PM
Answered by Expert


Under the experience of negative fied due to ligands or neutral molecules which have lone pair of electrons,the d-orbitals split into two levels i.e.t2g and eg.
When the complex is formed, the ligands destroy the degeneracy(same energy level) of these orbitals i.e.the orbitals have now different energies.In an isolated gaseous metal ion the five d-orbitals do all have same energy termed as degenerate.However,the energy of orbitals is raised because of repulsion between the field and the electrons on the metal.In most transition metal complexes either six or four ligands surround to metal giving octahedral or tetrahedral structures.
    In these two cases the field produced by the ligand is not spherically symmetrcal.Thus,the d-orbitals are not all affected equally by ligand field and thus become asymmetrical.
Answered by Expert 25th December 2011, 1:16 PM

Rate this answer

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Report an issue
Your answer has been posted successfully!