NEET Class neet Answered
Q.no. 17 - 20 please send me solutions sir
Asked by brijk456 | 22 Jul, 2019, 10:31: PM
Expert Answer
Please ask one question in one posting. Only question 17 is answered.
Equation for displacement :- x = A sinωt ...................(1)
Equation for velocity :- v = dx/dt = Aω cosωt ...................(2)
where A is amplitude, ω is angular velocity.
we have amplitude A = 4 cm, at mean position velocity = 10 cm/s
at mean position t = 0, then from eqn.(2), we have 10 = 4ω .............(3)
if velocity is 5 cm/s, from eqn.(2) , we have , 5 = 10 cos(ωt) or cos(ωt) = (1/2) or ωt = π/3
distance of the particle is obtained from eqn.(1), x = 4 sin(π/3) = 4×(√3/2) = 2√3 cm
Answered by Thiyagarajan K | 23 Jul, 2019, 12:31: PM
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