NEET Class neet Answered

Q 35 Ans option 1

Asked by manasvijha | 20 Mar, 2019, 06:05: PM

Expert Answer

For first order kinetics, rate is directly proportional to concetration of ractants.

Rate subscript 1 space equals space straight k left parenthesis straight a minus straight x right parenthesis subscript 1 Rate subscript 2 space equals space straight k left parenthesis straight a minus straight x right parenthesis subscript 2 therefore Rate subscript 1 over Rate subscript 2 equals space fraction numerator left parenthesis straight a minus straight x right parenthesis subscript 1 over denominator left parenthesis straight a minus straight x right parenthesis subscript 2 end fraction space equals space fraction numerator 0.04 over denominator 0.03 end fraction

Considering the integrated rate law:

straight k space equals space fraction numerator 2.303 over denominator left parenthesis straight t subscript 2 minus straight t subscript 1 right parenthesis end fraction space log space fraction numerator left parenthesis straight a minus straight x right parenthesis subscript 1 over denominator left parenthesis straight a minus straight x right parenthesis subscript 2 end fraction straight k space equals space fraction numerator 2.303 over denominator left parenthesis 20 minus 10 right parenthesis end fraction space log space fraction numerator 0.04 over denominator 0.03 end fraction straight k space equals space fraction numerator 2.303 over denominator left parenthesis 20 minus 10 right parenthesis end fraction space log space 4 over 3 straight k space equals space fraction numerator 2.303 over denominator left parenthesis 20 minus 10 right parenthesis end fraction space open parentheses 0.6020 space minus 0.4771 close parentheses straight k space equals space fraction numerator 2.303 over denominator 10 end fraction space left parenthesis 0.1249 right parenthesis

For first order kinetics

t subscript 1 divided by 2 end subscript space equals space 0.693 divided by k space equals space fraction numerator space 0.693 over denominator k end fraction equals space fraction numerator space 0.693 over denominator left parenthesis 2.303 right parenthesis left parenthesis 0.1249 right parenthesis divided by 10 end fraction equals space 24.1 s

Answered by Ramandeep | 20 Mar, 2019, 07:06: PM

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