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ICSE Class 10 Answered

prove:     sinA (1+tanA) + cosA (1+cotA) = secA + cosecA
Asked by reeshitaanand | 08 Feb, 2016, 07:29: PM
answered-by-expert Expert Answer
sinA space open parentheses 1 plus tanA close parentheses space plus space cosA open parentheses 1 plus cotA close parentheses equals sinA open parentheses 1 plus sinA over cosA close parentheses plus cosA open parentheses 1 plus cosA over sinA close parentheses equals sinA open parentheses fraction numerator cosA plus sinA over denominator cosA end fraction close parentheses plus cosA open parentheses fraction numerator sinA plus cosA over denominator sinA end fraction close parentheses equals sinA open parentheses fraction numerator sinA plus cosA over denominator cosA end fraction close parentheses plus cosA open parentheses fraction numerator sinA plus cosA over denominator sinA end fraction close parentheses equals open parentheses sinA plus cosA close parentheses open square brackets sinA over cosA plus cosA over sinA close square brackets equals open parentheses sinA plus cosA close parentheses open square brackets fraction numerator sin squared straight A plus cos squared straight A over denominator sinAcosA end fraction close square brackets equals open parentheses sinA plus cosA close parentheses open square brackets 1 over sinAcosA close square brackets equals fraction numerator sinA plus cosA over denominator sinAcosA end fraction equals sinA over sinAcosA plus cosA over sinAcosA equals 1 over cosA plus 1 over sinA equals secA plus cosecA
Answered by Vijaykumar Wani | 09 Feb, 2016, 10:39: AM
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