ICSE Class 10 Answered
Given: cosA = 5/13
evaluate: (I)sin A - cotA/ 2tanA
(ii)cotA + 1/tanA
Asked by grandhienterprises13 | 08 Aug, 2019, 07:16: AM
Expert Answer
cos A = 5/13
Using sin2 A = 1 - cos2 A
we get sin A = 12/13
tan A = sin A/cos A = 12/5 and cot A = 1/tan A = 5/12
(ii) cotA + 1/tanA = cot A + cot A = 2 cot A = 10/12 = 5/6
Answered by Sneha shidid | 08 Aug, 2019, 10:31: AM
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