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Please solve the following question

Asked by Balbir 7th October 2017, 11:15 PM
Answered by Expert
Answer:
begin mathsize 16px style integral fraction numerator square root of cos 2 straight x end root over denominator cosx end fraction dx
integral fraction numerator square root of begin display style fraction numerator 1 minus tan squared straight x over denominator 1 plus tan squared straight x end fraction end style end root over denominator cos begin display style straight x end style end fraction dx
integral fraction numerator square root of begin display style fraction numerator 1 minus tan squared straight x over denominator sec squared straight x end fraction end style end root over denominator cos begin display style straight x end style end fraction dx
integral fraction numerator square root of 1 minus tan squared straight x end root over denominator secx cross times cosx end fraction dx
integral fraction numerator square root of 1 minus tan squared straight x end root over denominator 1 end fraction dx
put space tan space straight x space equals space sint
and space solve space it space further.
end style
Answered by Expert 21st December 2017, 3:17 PM
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