e^x (x-1/x^2)dx
Asked by Ketoli | 7th Nov, 2019, 07:43: PM
Expert Answer:
The question should be like this
Integrate ex (x - 1/x2)dx
I = integration ex (1/x - 1/x2) dx
Let f(x) = 1/x then f'(x) = -1/x2
I = integration of ex [f(x) + f'(x)] dx
I = ex f(x) + c = ex × 1/x + c
Answered by Sneha shidid | 10th Nov, 2019, 07:58: PM
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