CBSE Class 11-science Answered

$E v a l u a t e space limit as x rightwards arrow 0 of open parentheses fraction numerator 1 plus 7 x over denominator 1 minus 9 x end fraction close parentheses to the power of 1 over x end exponent$ Please provide solution to this question

Asked by Topperlearning User | 16 Nov, 2016, 04:27: AM

Expert Answer

$limit as x rightwards arrow 0 of open parentheses fraction numerator 1 plus 7 x over denominator 1 minus 9 x end fraction close parentheses to the power of 1 over x end exponent equals e to the power of limit as x rightwards arrow 0 of 1 over x log open parentheses fraction numerator 1 plus 7 x over denominator 1 minus 9 x end fraction close parentheses end exponent limit as x rightwards arrow 0 of 1 over x log open parentheses fraction numerator 1 plus 7 x over denominator 1 minus 9 x end fraction close parentheses equals limit as x rightwards arrow 0 of fraction numerator 7 log left parenthesis 1 plus 7 x right parenthesis over denominator 7 x end fraction minus limit as x rightwards arrow 0 of fraction numerator negative 9 log left parenthesis 1 minus 9 x right parenthesis over denominator negative 9 x end fraction equals 7 plus 9 equals 16 e to the power of limit as x rightwards arrow 0 of 1 over x log open parentheses fraction numerator 1 plus 7 x over denominator 1 minus 9 x end fraction close parentheses end exponent equals e to the power of 16$

Answered by | 16 Nov, 2016, 06:27: AM

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CBSE Class 11-science Answered

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