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T h e space c o e f f i c i e n t space o f space v a r i a t i o n space o f space 2 space d a t a space s e t s space a r e space C subscript 1 space a n d space C subscript 2 space r e s p e c t i v e l y.
I f space i n space t h e space f i r s t space d a t a space s e t space e a c h space v a l u e space i s space i n c r e a s e d space b y space 2 sigma subscript 1 space a n d space i n space t h e space s e c o n d
d a t a space s e t space e a c h space v a l u e space i s space d e c r e a s e d space b y space 2 sigma subscript 2 space t h e n space f i n d space t h e space n e w space c o e f f i c i e n t space o f space v a r i a t i o n s
f o r space t h e space d a t a space s e t s. left parenthesis sigma subscript 1 space a n d space sigma subscript 2 space a r e space t h e space s tan d a r d space d e v i a t i o n s space o f space t h e space d a t a space s e t s right parenthesis

Please provide solution to this question

Asked by Topperlearning User 19th November 2016, 3:10 AM
Answered by Expert
Answer:

C o n s i d e r space f i r s t space d a t a space s e t colon
C subscript 1 equals fraction numerator sigma subscript 1 over denominator space stack x subscript 1 with bar on top end fraction space w h e r e space stack x subscript 1 with bar on top equals m e a n
W h e n space e a c h space d a t a space i s space i n c r e a s e d space b y space 2 sigma subscript 1 space t h e n space t h e space m e a n space b e c o m e s space space stack x subscript 1 with bar on top plus 2 sigma subscript 1
T h e r e space w i l l space b e space n o space c h a n g e space i n space t h e space s tan d a r d space d e v i a t i o n.
N e w space C. V space
C to the power of apostrophe subscript 1 equals fraction numerator sigma subscript 1 over denominator space stack x subscript 1 with bar on top plus 2 sigma subscript 1 end fraction equals fraction numerator fraction numerator sigma subscript 1 over denominator space stack x subscript 1 with bar on top end fraction over denominator 1 plus 2 fraction numerator sigma subscript 1 over denominator space stack x subscript 1 with bar on top end fraction end fraction equals fraction numerator C subscript 1 over denominator 1 plus 2 C subscript 1 end fraction
C o n s i d e r space S e c o n d space d a t a space s e t colon
C subscript 2 equals fraction numerator sigma subscript 2 over denominator space stack x subscript 2 with bar on top end fraction space w h e r e space stack x subscript 2 with bar on top equals m e a n
W h e n space e a c h space d a t a space i s space d e c r e a s e d space b y space 2 sigma subscript 2 space t h e n space t h e space m e a n space b e c o m e s space space stack x subscript 2 with bar on top plus 2 sigma subscript 2
T h e r e space w i l l space b e space n o space c h a n g e space i n space t h e space s tan d a r d space d e v i a t i o n.
N e w space C. V space
C to the power of apostrophe subscript 2 equals fraction numerator sigma subscript 2 over denominator space stack x subscript 1 with bar on top minus 2 sigma subscript 2 end fraction equals fraction numerator fraction numerator sigma subscript 2 over denominator space stack x subscript 2 with bar on top end fraction over denominator 1 minus 2 fraction numerator sigma subscript 2 over denominator space stack x subscript 2 with bar on top end fraction end fraction equals fraction numerator C subscript 2 over denominator 1 minus 2 C subscript 2 end fraction

Answered by Expert 19th November 2016, 5:10 AM
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