CBSE Class 9 Answered
Please Explain NCERT Textbook, exercise 10.4 , Q5 and Q6.
Asked by Radha Pandey | 05 Jan, 2015, 01:29: PM
Expert Answer
Q5.Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5 m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6 m each, what is the distance between Reshma and Mandip?
Draw perpendiculars OA and OB on RS and SM respectively.
Let R, S and M be the position of Reshma, Salma and Mandip respectively.
Let R, S and M be the position of Reshma, Salma and Mandip respectively.
OA and OB are the perpendiculars from the centre to the chord RS and SM.
Since the perpendicular from the centre bisects the chord, we have,
AR = AS = = 3cm
OR = OS = OM = 5 m (radii of circle)
In ytriangle OAR
OA2 + AR2 = OR2
OA2 + (3 m)2 = (5 m)2
OA2 = (25 - 9) m2 = 16 m2
OA = 4 m
We know that in an isosceles triangle altitude divides the base, so in RSM
RCS will be of 90o and RC = CM
Area of ORS = OARS
In ytriangle OAR
OA2 + AR2 = OR2
OA2 + (3 m)2 = (5 m)2
OA2 = (25 - 9) m2 = 16 m2
OA = 4 m
We know that in an isosceles triangle altitude divides the base, so in RSM
RCS will be of 90o and RC = CM
Area of ORS = OARS
Now consider the triangle ORS with OS as base. Then RC is the altitude of the triangle ORS.
Therefore,
Answered by Vimala Ramamurthy | 06 Jan, 2015, 10:22: AM
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