CBSE Class 10 Answered
please explain in detail?
Asked by abinash.gupta003 | 22 Dec, 2017, 01:41: PM
Expert Answer
Upward velocity of ball w.r.t lift is ulet the upward acceleration and downward acceleration be aresultant acceleration = -g-a = -(g +a)Ball reached a height h and comes back to the man so dispalcemnet would be zeroh=ut1 +(1/2)at120 = ut1 -(1/2)(a + g)t12ut1=(1/2)(a +g)t12a+ g = 2u/t1t1= 2u/(a+g)similaralry for case when man is descending downt2=2u / (g-a)This hint should be able to help to get the answer
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