NEET Class neet Answered
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Asked by Prashant DIGHE | 10 Jan, 2020, 10:10: PM
Expert Answer
In hydrogen like atom , energy of orbit that has quantum number n = (- 13.6/n2 ) eV
Hence frequency ν of radiaton that arises due to orbital transition of electron from quantum number n to (n-1) is
proportional to [ 1/(n-1)2 - 1/n2 ] ;
Hence we get ν = k (2n-1) / [ n2 (n-1)2 ] ................. (1)
where k is constant. when n->∞ , we have (2n-1) ≈ 2n and (n-1)≈ n
Using these approximations, we get ν ≈ k (2n) / n4 = k [ 2/n3 ]
Answered by Thiyagarajan K | 11 Jan, 2020, 12:34: PM
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