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please answer this

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Asked by Prashant DIGHE 16th February 2020, 10:09 PM
Answered by Expert
Answer:
option (1) is coorect.
 
The reaction is:
 
CH identical to straight C minus CH with vertical line below minus CH subscript 3 space end subscript space space space space rightwards arrow with straight C subscript 2 straight H subscript 6 MgBr on top space space space 2 straight C subscript 2 straight H subscript 6 space plus space Product
space space space space space space space space space space space space space space space OH
space space space space space space space space 1 space mole space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2 space mole
space space space space space space space space 1 space mole space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2 cross times 22.4 space lit
 
Given:
 
Mass of but-3 -yn-2-ol = 0.21 gm
 
Molar mass of but-3 -yn-2-ol = 70 
 
No. of molesequals fraction numerator 0.21 over denominator 70 end fraction
                   = 0.003 mol
 
So 0.003 mole of but-3 -yn-2-ol will give
 
 
equals fraction numerator 2 cross times 22.4 cross times 0.003 over denominator 1 end fraction
= 0.1344 lit
 
= 134.4 ml
 
The volume of gas (C2H6) evolved is 134.4 ml
Answered by Expert 17th February 2020, 12:17 PM
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