NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 13 Jan, 2020, 10:25: PM
Expert Answer
Let P be the power radiated (i.e. energy per second ) by sun.
Received power on unit area of earth surface ( neglecting atmospheric attenuation ) = P/(4πr2 )= 1200 W/m2
where r is the sun-to-earth distance
Hence Radiated power from sun P = 1200 × 4π × ( 1.5 × 1011 )2
Energy lost in one day = power × time = 1200 × 4π × ( 1.5 × 1011 )2 × 86400 J
By using the relation E = Δm c2 , where Δm is mass converted to energy and c is speed of light,
we get mass Δm lost by sun in one day as, Δm = [ 1200 × 4π × ( 1.5 × 1011 )2 × 86400 J ] / ( 9 × 1016 ) = 3.26 × 1014 kg
Answered by Thiyagarajan K | 14 Jan, 2020, 10:39: AM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by tejaskadiyan148 | 05 May, 2024, 11:52: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by hardikmittal25 | 03 May, 2024, 02:57: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sa1033278 | 02 May, 2024, 07:37: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
