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Asked by Prashant DIGHE | 31 Jan, 2020, 10:26: PM
answered-by-expert Expert Answer
Electric field in electromagnetic wave, begin mathsize 14px style stack E space with rightwards arrow on top space equals space E subscript o space fraction numerator i with rightwards arrow on top plus space j with rightwards arrow on top over denominator square root of 2 end fraction cos open parentheses k space z space plus space omega space t close parentheses end style ..........................(1)
at time t = 0,  at location ( 0, 0, π/k ), electric field begin mathsize 14px style stack E space with rightwards arrow on top space equals space minus E subscript o space fraction numerator i with rightwards arrow on top plus space j with rightwards arrow on top over denominator square root of 2 end fraction end style
Direction of field is parallel to x-y plane.
 
positively charged particle is moving with velocity vo begin mathsize 14px style k with rightwards arrow on top end style , i.e moving in z-direction and perpendicular to the electric field.
Hence force on positive charge is zero
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