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Asked by Prashant DIGHE | 08 Oct, 2019, 09:45: PM
answered-by-expert Expert Answer
 
Upward thrust given by liquid to floating solid = V×(ρl - ρs )×g
 
where V is immersed volume of solid, ρl is liquid density,  ρs is solid density and g is acceleration due to gravity
 
When the wooden block is immersed in oil and water, then uward thrust due to oil and water is balanced by weight of wooden block.
 
Let A is cross section area of wooden block.
 
Let density of wooden block is ρs , density of oil is ρoil and density of water is ρw
 
Upward thrust given by oil and water :-  6×10-2 × A × (ρoil - ρs ) × g + 4×10-2 × A × (ρw - ρs ) × g  ................(1)
 
weight of wooden block :- 10×10-2 × A × ρs × g  ........................(2)
 
by equating (1) and (2), we get, 10× ρs  = 6× (ρoil - ρs )  + 4× (ρw - ρs )  ..........(3)
 
from eqn. (3), we get density of wooden block, ρs = 380 kg/m3
Answered by Thiyagarajan K | 09 Oct, 2019, 10:44: AM
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