NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 29 Jan, 2020, 10:23: PM
Expert Answer
magnification m of compound microscope is given by, m = mo me = ( L/fo ) [ 1 + ( D/fe ) ]
where mo is magnificaion of objective lens that depends on tube length L and focal length fo of objective lens .
where me is magnification produced by eye-piece that depends on D = 25 cm which is near point of comfortable
viewing and fe is the focal length of eye piece.
we are given m = 375, L = 150 mm, fo = 5 mm
hence [ 1 + ( D/fe ) ] = ( 375 × 5 ) / 150 = 12.5
hence ( D/ fe ) 11.5 ; fe = 250 / 11.5 ≈ 22 mm
Answered by Thiyagarajan K | 30 Jan, 2020, 04:30: PM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by tejaskadiyan148 | 05 May, 2024, 11:52: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by hardikmittal25 | 03 May, 2024, 02:57: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sa1033278 | 02 May, 2024, 07:37: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
