NEET Class neet Answered
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Asked by Prashant DIGHE | 13 Jan, 2020, 10:28: PM
Expert Answer
If power level of reactor is 200 MW, then electrical energy Eel produced in one day ( 86400 s) = 200 × 106 × 86400 J
If efficiency is 25% , then thermal energy Eth produced in one day is given by
Eth = 200 × 106 × 86400 × (100/25) = 6.912 × 1013 J .........................(1)
Energy released per fusion reaction is calculated by mass difference between 2 deuterium nucleus and one Helium nucleus.
mass difference Δm in amu = (2×2.0141) - 4.0026 = 0.0256 amu
energy produced per fusion reaction = Δm c2 = 0.0256 × 1.673 × 10-27 × 9 × 1016 J = 3.85 × 10-12 J
if (2×2.0141) amu of deuterium gives 3.85 × 10-12 J ,
then energy E released by 1 gm of deuterium in fusion reaction is given by,
E = ( 3.85 × 10-12 ) / ( 2×2.0141×1.673 × 10-24 ) = 5.713 × 1011 J .........................(2)
From eqn.(1) and eqn.(2), we get mass m of deuterium per day for 200 MW reactor as,
m = Eth / E = 6.912 × 1013 / ( 5.713 × 1011 ) ≈ 121 gm
Answered by Thiyagarajan K | 14 Jan, 2020, 12:31: PM
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