NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 29 Dec, 2019, 09:56: PM
Expert Answer
impedence of 5 mH inductance, XL = 5 × 10-3 × 2000 = 10 Ω
impedence of 50 μF Capacitance, XC = 1/ (50 × 10-6 × 2000) = 10 Ω
Resistance R in the circuit = 6+4 = 10 Ω ( 4Ω resistance of inductance coil is included )
Effective impedence of Circuit Z = [ R2 +( XC - XL )2 ]1/2 = [ 102 +(10-10)2 ]1/2 = 10 Ω .
Hence peak current = vm / Z = 20/10 = 2 A
RMS current = 2 × 0.707 = 1.41 A ( Current reading in Ammeter is RMS current )
Since phase difference between inductor voltage and Capactor voltage is 180o out of phase
and their impedences are equal, net voltage across inductor and capacitor will be zero.
But inductor has coil resistance 4Ω . Hence voltage drop due to this coil resistance appears in voltmeter reading.
Hence voltmeter reading = 4 × 1.41 = 5.64 V
Answer:- Voltmeter and ammeter readings are 5.64 V and 1.41 A
Answered by Thiyagarajan K | 30 Dec, 2019, 08:39: AM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by sa1033278 | 02 May, 2024, 07:37: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
