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Asked by Prashant DIGHE | 02 Mar, 2020, 08:50: PM

Expert Answer

Given:

t₁ for H₂ = 5 sec

t₂ = ?

We know,

by using Graham's law,

rate of diffusion is inversally proportional to molar mass.

straight r subscript 1 over straight r subscript 2 space equals space square root of fraction numerator straight M subscript 2 over denominator straight M 1 end fraction end root

Also we have,

straight t subscript 2 over straight t subscript 1 equals square root of straight M subscript 2 over straight M subscript 1 end root

For He,

t₂ =

square root of 4 over 2 end root open parentheses 5 close parentheses

t₂ =

square root of 2 cross times 5

≠ 10 sec

For O₂

t₂ =

square root of 32 over 2 end root cross times space 5

t₂ = 20 sec.

For CO

t₂ =

square root of 28 over 2 end root cross times 5

t₂ =

square root of 7 cross times 5

t₂ ≠25 s

For CO₂

t₂ =

square root of 44 over 2 end root cross times 5

square root of 22 cross times 5

t₂ ≠ 55 s

Therefore option (2) is correct.

For O₂ : 20 seconds

Answered by Varsha | 03 Mar, 2020, 11:59: AM

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