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![question image](https://images.topperlearning.com/topper/new-ate/topr_1092034836623312P202003012138441.jpeg)
Asked by Prashant DIGHE | 03 Mar, 2020, 22:09: PM
Option (1) is correct.
Given:
Volume of container = 20 L
Temperature, t = 400 K
Pressure = 0.4 atm
The given reaction is,
SrCO3(s)
SrO(s) + CO2(g)
![rightwards harpoon over leftwards harpoon](https://images.topperlearning.com/topper/tinymce/cache/2f230865a293d75ad92dba43125f48c7.png)
kp = 1.6 atm
PCO2 = 1.6 atm = Maximum pressure of CO2
Volume of conatainer at this stage is;
![PV space equals space nRT](https://images.topperlearning.com/topper/tinymce/cache/5b6c999466831893a80aeaf87ea86238.png)
![straight V space equals nRT over straight P](https://images.topperlearning.com/topper/tinymce/cache/a1d2b0f245caad9948a045abde37493d.png)
n = constant, as reaction was not at equilibrium.
![straight n equals space PV over RT](https://images.topperlearning.com/topper/tinymce/cache/9f3803a2acdf66d6a5c664f49a77d19d.png)
![straight n equals fraction numerator 0.4 cross times 20 over denominator RT end fraction](https://images.topperlearning.com/topper/tinymce/cache/a4aed7c8cfb70f70f959fbfb81fe856c.png)
From eq(1) and (2)
![straight V equals space open parentheses fraction numerator 0.4 cross times 20 over denominator RT end fraction close parentheses open parentheses fraction numerator RT over denominator 1.6 end fraction close parentheses
straight V space equals space 5 space straight L](https://images.topperlearning.com/topper/tinymce/cache/96c154c026af19492bb89c8b7ddcbcd7.png)
The maximum volume of the container at maximum pressure is 5 L.
Answered by Varsha | 04 Mar, 2020, 13:18: PM
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