NEET Class neet Answered
please answer this
Asked by Prashant DIGHE | 14 Jan, 2020, 10:09: PM
Expert Answer
Activity of radioactive sample after 3 half life = c × 2-3 = 0.125c
Activity found in the leftover sample = c/10 = 0.1c
Activity is proportional to volume
Volume of remaining sample = (0.1c / 0.125 c) × 100 cm3 = 80 cm3
Answered by Thiyagarajan K | 15 Jan, 2020, 07:28: AM
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