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Asked by Prashant DIGHE 7th December 2019, 10:18 PM
Figure shows two wires which are placed in x-y plane at a distance x = +a and x  = -a .
Currents through the wire are in opposite direction.

Magnetic field B1 at O due to both wire = [ μo i / (2πa) ] + [ μo i / (2πa) ] = [ μo i / (πa) ] ......................(1)

Magnetic field B2 at P due to both wire = [ μo i / (2πa) ] - [ μo i / (2π×3a) ]
Magnetic field B2 at P = ( μo i / (2πa) ) [ 1 - (1/3) ] = ( μo i / (πa) ) (1/3) ..................(2)

From eqn.(1) and (2),  we get the ratio B1 : B2 = 3
Answered by Expert 8th December 2019, 12:37 PM
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