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CBSE Class 10 Answered

in triangle ABC is a right triangle right angle B and sin c is equal to 12 by 25 find the value of sin A cos c minus cos A sin c
Asked by sandipmukherjee16536 | 14 Sep, 2023, 08:16: PM
answered-by-expert Expert Answer
If sinC = AB/ AC = 12/25 , then side BC  = begin mathsize 14px style square root of A C squared minus A B squared end root space equals space square root of 25 squared minus 12 squared end root space equals space 21.93 end style
sinA = 21.93/25  , cosA = 12/25 and cosC = 21.93/25
 
sinA cosC - cosA sinC = (21.93 / 25 ) ( 21.93 /25) - (12/25) (12/25) = (1/25)2 [  (21.93)2 - (12)2 ]
 
 
sinA cosC - cosA sinC = (1/25)2  [ 33.93 × 9.93 ] = 0.539 
 
Answered by Thiyagarajan K | 19 Sep, 2023, 08:57: PM

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