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In Figure  DE II OQ and DF II OR show that EF II QR. 

 

 

 

Asked by Topperlearning User 26th July 2017, 1:40 PM
Answered by Expert
Answer:

 

    In PQO;  DE II  OQ                

                    (BPT)

                   Also, in POR; DF II  OR

                    (BPT)

                   From (1) and (2) we have

                    

From converse of BPT, we have EF II QR.  Hence proved

Answered by Expert 26th July 2017, 3:40 PM
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