NEET Class neet Answered
if the standard molar enthalpy change for combustion of graphite powder is -3.45×10²kj mol–¹the amount of heat generated on combustion of 2g of graphite powder is
Asked by shaiksufiyan.klr | 13 Jan, 2024, 11:49: AM
Expert Answer
Dear Student,
Moles of graphite = 2 g / 12 g / mol
Heat released = Standard enthalpy × number of moles = × 102 kJ / mol = 57.5 kJ
Answered by | 13 Jan, 2024, 11:33: PM
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