CBSE Class 12-science Answered
how to find oxidation number of compound and list of complex compound with oxidation numbr
Asked by devsingh71 | 15 Jan, 2015, 09:49: PM
Expert Answer
Oxidation number: In the [PtCl6]2- ion for example, each chloride ion has an oxidation number of –1, so the oxidation number of Pt must be +4. If the ligands do not bear net charges the oxidation number of the metal is equal to the charge of the complex ion. Thus in [Cu(NH3)4]2+ each NH3 is neutral, so the oxidation number of copper is +2.
Some examples are as follows:
(i) [MnCl6] 4-
(-4) = y + (-6) hence y = +2
(ii) [Fe(CN)6]3-
(-3) = y + (-6) hence y = +3
(iii) [Cr(NH3)6]3+
(+3) = y + (0) hence y = +3
(iv) [Ni(en)3]2+
(+2) = y + (0) hence y = +2
Answered by Prachi Sawant | 16 Jan, 2015, 06:30: PM
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