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From a metallic hydroxide of mass 1.872 g 1.224 g metallic oxide is obtained. Determine the equilibrium of the metal.
Asked by bishaldas20062006 | 08 Apr, 2022, 02:27: PM
answered-by-expert Expert Answer
This question may be asking about equivalent weight not equilibrium.
 
fraction numerator Weight space of space Metal space Hydroxide over denominator Weight space of space Metal space Oxide end fraction equals fraction numerator straight E subscript straight M plus straight E subscript OH to the power of minus end subscript over denominator straight E subscript straight M plus straight E subscript straight O to the power of minus end subscript end fraction fraction numerator 1.520 over denominator 0.995 end fraction equals fraction numerator straight x plus 17 over denominator straight x plus 8 end fraction 1.520 straight x space plus space 1.520 cross times 8 equals 0.995 straight x plus 0.995 cross times 17 1.520 straight x space plus 12.160 equals 0.995 straight x plus 16.915 0.525 straight x equals 4.755 straight x equals fraction numerator 4.755 over denominator 0.525 end fraction equals 9.057
Answered by Ravi | 12 Apr, 2022, 11:43: AM
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