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CBSE Class 12-science Answered

find the number of electrons present in an 8g gold pin. given - molar mass of gold = 197g/mol , electrons per atom in gold = 79 and avogadro's number = 6.023*10 23 g-1 mol-1.
Asked by malhanmuskan2003 | 24 Jun, 2020, 02:12: PM
answered-by-expert Expert Answer
N u m b e r space o f space m o l e s space o f space g o l d space i n space 8 g equals 8 over 197 N o space o f space a t o m s space o f space g o l d space p r e s e n t space i n space 8 g space equals 8 over 197 cross times 6.02 cross times 10 to the power of 23 N o w space 1 space a t o m space o f space g o l d space h a s space 79 space e l e c t r o n s T h e r e f o r e space 8 over 197 cross times 6.02 cross times 10 to the power of 23 space a t o m s space space h a s space equals 8 over 197 cross times 6.02 cross times 10 to the power of 23 cross times 79 space e l e c t r o n s. equals 1.93 cross times 10 to the power of 24 e l e c t r o n s
Answered by Utkarsh Lokhande | 24 Jun, 2020, 02:38: PM

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