CBSE Class 12-commerce Answered
Find the dimensions of the rectangle of area 96 cm square whose perimeter is the least
Asked by saketbhupal | 20 Nov, 2018, 11:26: PM
Expert Answer
If l is length of rectangle , then its breadth is 96/l because area of rectangle is 96 sq.cm.
Perimeter P = 2( l + (96/l) ] ..................(1)
if we differentiate eqn.(1) with respect to l, we get, ( dP/dl ) = 2 - (192/ l2 ) .......................(3)
to get maximum, we equate eqn.(3) to zero and we get the value of l for maximum P.
Hence 2 - (192/ l2 ) = 0 or l = 
Hence dimensions of rectangle to get maximum perimeter are l = and b =
and b =
Answered by Thiyagarajan K | 20 Nov, 2018, 11:47: PM
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