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find equation and centre of the circle passing through the points(3,4),(3,2)&(1,4)
Asked by maramharinadh98 | 01 Nov, 2023, 09:45: AM
answered-by-expert Expert Answer
Equation of Circle passing through  (x,y) is
 
 begin mathsize 14px style x squared plus y squared plus 2 g x plus 2 f y plus c space equals space 0 end style  .......................... (1)
 
If circle is passing through ( 3, 4 ) , then by substituting x = 3 and y = 4 , we get
 
6 g + 8 f + c = -25 .....................................(2)
 
If circle is passing through ( 3, 2 ) , then by substituting x = 3 and y = 2 , we get
 
6 g + 4 f + c = -13 .....................................(3)
 
 
If circle is passing through ( 1, 4 ) , then by substituting x = 1 and y = 4 , we get
 
2 g + 8 f + c = -17 .....................................(4)
 
Subtracting eqn.(3) from eqn.(2) , we get ,
 
4 f = -12  or  f = -3
 
By substituting f = -3 in eqn.(2) and (4) , we get following simultaneous linear equations
 
6 g + c = -1
 
2 g + c = 7
 
By solving above equations , we get ,  g = - 2 and  c = 11
 
Hence equation of circle from eqn.(1) is
 
begin mathsize 14px style x squared plus y squared minus 4 x space minus space 6 y space plus 11 space equals space 0 end style 
Radius = begin mathsize 14px style square root of g squared plus f squared minus c end root space equals space square root of 4 plus 9 minus 11 end root space equals space square root of 2 end style



 
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