# JEE Class main Answered

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Asked by vasavipanchakoti | 22 Mar, 2024, 08:16: PM

Expert Answer

Given circle is

x^{2} + y^{2} - 2x + 8y -23 = 0 \ \ \ ..................... (1)

Centre C and radius r of circle " x^{2} + y^{2} + 2gx + 2fy +c = 0 " are given by

C = ( -g, -f )

Centre of circle given by eqn.(1) is ( 1, -4)

power of point P (2 , 3 ) is ( PC )^{2} - r^{2}

( PC )^{2} = (2 -1)^{2} + ( 3 +4 )^{2} = 50 ;

Power of point P(2,3) = 50 - 40 = 10

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