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NEET Class neet Answered

explain
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Asked by srushtimahajan125 | 03 Jan, 2023, 06:14: PM
answered-by-expert Expert Answer
Dear Student,
Vapour pressure of pure water (solvent) at100°C,  po = 760 mm

Vapour pressure of solution, p = ?

Wt. of solvent, W = 33 g

Wt. of solute, w = 3 g

Mol. wt. of water = 18

Mol. wt. of sugar (C12H22O11) = 342

According to Raoult’s law,

p° − p / p° = wM / WM 

​p = p° − (wM/WM) × p°

P = 760 – [(3×18 / 342×33) ×760]

P = 756.9 mm Hg

Hence, correct answer option is 'b'.

Answered by | 04 Jan, 2023, 05:32: PM
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