NEET Class neet Answered
explain
Asked by srushtimahajan125 | 03 Jan, 2023, 06:14: PM
Expert Answer
Dear Student,
Vapour pressure of pure water (solvent) at100°C, po = 760 mm
Vapour pressure of solution, p = ?
Wt. of solvent, W = 33 g
Wt. of solute, w = 3 g
Mol. wt. of water = 18
Mol. wt. of sugar (C12H22O11) = 342
According to Raoult’s law,
p° − p / p° = wM / WM
p = p° − (wM/WM) × p°
P = 760 – [(3×18 / 342×33) ×760]
P = 756.9 mm Hg
Hence, correct answer option is 'b'.
Answered by | 04 Jan, 2023, 05:32: PM
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