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Eq of circle passing through non collinear A,B,C is
Asked by ramasuryakumarivasamsetti | 26 Oct, 2023, 09:19: PM
answered-by-expert Expert Answer
Equation of circle :-
 
begin mathsize 14px style x squared plus y squared plus 2 g space x space plus space 2 f space y space plus space c space equals space 0 end style  . .. . . . . . . . . . . . . .  (1)
 
If the circle given in eqn.(1) is passing through  A ( x1 , y1) , then we get
 
 
begin mathsize 14px style x subscript 1 squared plus y subscript 1 squared plus 2 g space x subscript 1 space plus space 2 f space y subscript 1 space plus space c space equals space 0 end style ............................(2)
 
Similarly, If the circle given in eqn.(1) is passing through  B ( x2 , y2) and C ( x3, y3) , then we get
 
begin mathsize 14px style x subscript 2 squared plus y subscript 2 squared plus 2 g space x subscript 2 space plus space 2 f space y subscript 2 space plus space c space equals space 0 end style .............................. (3)
 
begin mathsize 14px style x subscript 3 squared plus y subscript 3 squared plus 2 g space x subscript 3 space plus space 2 f space y subscript 3 space plus space c space equals space 0 end style ...............................(4)
 
We get the following three linear equations from eqn.(2) , eqn.(3) and eqn.(4)
 
 
begin mathsize 14px style space 2 g space x subscript 1 space plus space 2 f space y subscript 1 space plus space c space equals space negative x subscript 1 squared minus y subscript 1 squared end style
begin mathsize 14px style space 2 g space x subscript 2 space plus space 2 f space y subscript 2 space plus space c space equals space negative x subscript 2 squared minus y subscript 2 squared end style
 
begin mathsize 14px style space 2 g space x subscript 3 space plus space 2 f space y subscript 3 space plus space c space equals space negative x subscript 3 squared minus y subscript 3 squared end style
We can solve the above linear equations to get the unknowns  g, f, and c in terms of given coordintaes of A, B and C .
 
By substituting g, f and c in eqn.(1) , we get the required equation of circle that is passing through the points A, B and C
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
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