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Diagonal AC of a parallelogram bisects A. Show that:

(i) it bisects C also

(ii) ABCD is a rhombus

Asked by Topperlearning User 4th June 2014, 1:23 PM
Answered by Expert
Answer:

(i) 1 = 2 (given)

But 1 = 4, 2 = 3 (alt. int. angles)

3 = 4

AC bisects C

(ii) Now, 1 = 4, 2 = 3 (alt. int. angles)

AC = AC (Common)

(by ASA rule)

BC = DC (cpct)

But, AB = DC [Given] AB = BC = CD = AD

Hence, ABCD is a rhombus.

Answered by Expert 4th June 2014, 3:23 PM
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