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ABCD is a Rhombus in which BC = 25cm, AD = 24cm. Find the sum of lengths of the diagonals.
Asked by riya.yanamandra | 19 Oct, 2020, 06:45: AM Expert Answer

Diagonals of a rhombus are perpendicular to each other.

In triangle AOB, we have:

AO = 24 cm

AB = 25 cm

So, by Pythagoras theorem, we have:

BO = square root [(25)2 - (24)2] = 7 cm

Also, the diagonals of a rhombus bisect each other.

So, AC = 2AO = 48 cm

and BD = 2BO = 14 cm

Thus, sum of lengths of diagonals = 48 cm + 14 cm = 62 cm

Answered by Renu Varma | 19 Oct, 2020, 10:54: AM
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