# Areas Related To Circles Free Doubts and Solutions

### CBSE - X - Mathematics - Areas Related to Circles

## No diagram is given. This is from revision exercise in RD Sharma. What is the other possible diagram for this question? is there any difference between circumference and perimeter of semi-circle? (i thought circumference is πr nd perimeter is πr+2r, am i right?)

**Divyaa**28th March 2017, 9:22 AM

### CBSE - X - Mathematics - Areas Related to Circles

##
In fig. APB and AQO are semicircles, and AO = OB. If the perimeter of the figure is 40 cm, find the area of the shaded region.

**Abha**14th February 2016, 2:35 PM

### CBSE - X - Mathematics - Areas Related to Circles

## how did you find 4(root 3- 1) from above step please send the expansion of area of AFE

**sankalpsamiti**8th February 2016, 4:00 PM

### CBSE - X - Mathematics - Areas Related to Circles

## explain the areas of sector and segment of a circle with image and vedio explain

**azamk4198**7th January 2016, 12:16 PM

### CBSE - X - Mathematics - Areas Related to Circles

## Prove that the tangent drawn at the mid point of an arc of a circle is parallel to the chord joining the end points of the arc.

**Saloni**16th March 2015, 8:31 PM

### CBSE - X - Mathematics - Areas Related to Circles

## three circles of radius 2cm touch one another externally.these circle are circumscribed by a cirlce of radius R=4.3 cm.find the value of R and area of d shaded region

**Chandana kiran**23rd February 2015, 12:48 AM

### CBSE - X - Mathematics - Areas Related to Circles

What are some examples of renewable sources of energy?

### CBSE - X - Mathematics - Areas Related to Circles

4*90x23 + cos30 =?

### CBSE - X - Mathematics - Areas Related to Circles

In the figure the boundary of the shaded region in the diagram consist of 4 semi-circular areas, two smallest being equal. if the diameter of the largest is 14cm and that of smallest is 3.5cm. calculate

(i) the lenght of the boundary

(ii) area of the shaded region

**Jaispee Saran**10th March 2014, 7:37 PM