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ICSE Class 9 Answered

Calculate the temperature to which gas must be heated so that the volume triples without any change in pressure the gas is originally at 57 degree Celsius and having a volume 1 150 cc
Asked by Syedhussain97047 | 14 Feb, 2019, 10:16: PM
answered-by-expert Expert Answer
From Charle's law we know fraction numerator V 1 over denominator V 2 end fraction equals fraction numerator T 1 over denominator T 2 end fraction
 
Here V1 = 1.150Ltrs ; V2 = 3 X V1 and T1 = 570C = 330K 
 
Putting the values to above equation we get , 
 
T2 = fraction numerator 330 cross times 3 V 1 over denominator V 1 end fraction space equals space 990 K space equals space 717 to the power of 0 C
Answered by Sumit Chakrapani | 15 Feb, 2019, 01:53: AM

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