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be and CF are two traiangle equal altitude of triangle abc using rhs congruence rule prove that the triangle abc is isosceles
Asked by arahant2008 | 07 Oct, 2021, 09:38: PM
answered-by-expert Expert Answer
In triangles BCF and CBE,
angle BFC equals angle CEB space space space... space left parenthesis Each space 90 to the power of straight o right parenthesis BC space equals space BC space space... space left parenthesis Common space side right parenthesis FC space equals space EB space space... space left parenthesis Given right parenthesis rightwards double arrow triangle BCF approximately equal to triangle CBE space space space... space left parenthesis By space RHS space congruence space rule right parenthesis rightwards double arrow angle FBC equals angle ECB space space... space left parenthesis CPCT right parenthesis In space triangle ABC comma angle ABC equals angle ACB rightwards double arrow AB equals AC space space space... space left parenthesis Sides space opposite space to space equal space angles space are space equal right parenthesis Hence comma space triangle ABC space is space an space isosceles space triangle.
Answered by Renu Varma | 23 Oct, 2021, 07:27: PM

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be and CF are two traiangle equal altitude of triangle abc using rhs congruence rule prove that the triangle abc is isosceles
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