ABC is an isosceles triangle with AB = AC. Bisectors of B and C intersect at O. Prove that BO = CO and AO bisects BAC.

Asked by Topperlearning User | 10th Aug, 2017, 12:46: PM

Expert Answer:

In ABC, AB = AC ABC = ACB

OBC = OCB               (BO and CO bisect equals)

BO = OC

In AOB and AOC

AO = AO

AB = AC

BO = OC

AOB  AOC                  (SSS congruence rule)

OAB = OAC              (c.p.c.t)

 AO bisects BAC.

Answered by  | 10th Aug, 2017, 02:46: PM