ABC is an isosceles triangle with AB = AC. Bisectors of B and C intersect at O. Prove that BO = CO and AO bisects BAC.
Asked by Topperlearning User | 10th Aug, 2017, 12:46: PM
In ABC, AB = AC ABC = ACB
OBC = OCB (BO and CO bisect equals)
BO = OC
In AOB and AOC
AO = AO
AB = AC
BO = OC
AOB AOC (SSS congruence rule)
OAB = OAC (c.p.c.t)
AO bisects BAC.
Answered by | 10th Aug, 2017, 02:46: PM
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