answer only the 15ᵗʰ question given below

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answer only the 15ᵗʰ question given below

Asked by sarveshvibrantacademy | 26 Mar, 2019, 11:32: AM

Expert Answer

From q. 14 it is clear that the answer to the question is option (C) i.e. - (2mm) sin (5t - 40x)

Thus, we can see that A_r = 2mm

Now, we know, string power α A²,

Thus,

P subscript i over P subscript r equals 6 squared over 2 squared equals 36 over 4 equals 9 space T h u s comma P o w e r space r e f l e c t e d space i s comma space P subscript r space equals P subscript i over 9

Now, we know,

P_t= P_i - P_r

Thus, the power transmitted,

P subscript t space equals space P subscript i space minus fraction numerator space P subscript i over denominator 9 end fraction equals 8 over 9 P subscript i space end subscript

Thus, the percentage of power transmitted by a heavier string through the joint is,

8 over 9 cross times 100 equals 88.88 percent sign space almost equal to 89 percent sign

Answered by Shiwani Sawant | 26 Mar, 2019, 02:52: PM

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