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Asked by jhajuhi19 | 25 Jul, 2021, 05:03: PM
answered-by-expert Expert Answer
Thisn question is based on stoichiometry of chemical equation.
space space space space space space space 2 NaOH plus CO subscript 2 rightwards arrow space Na subscript 2 CO subscript 3 space plus thin space straight H subscript 2 straight O space space space space space space space space 2 space space space space space space space space space space colon space space space 1 space space space space space 40 over 40 space space space space space space space space space space space space space 1 half space space space space equals 1 space mole space space space space space equals 1 half mole Total space mixture space of space CO space plus CO subscript 2 equals space 0.8 space moles 2 CO plus straight O subscript 2 rightwards arrow CO subscript 2 CO colon CO subscript 2 space equals 1 colon 1 If space mixture space is space completely space oxidized space than space moles space of space CO subscript 2 equals space 0.8 space moles We space have space already space used space 0.5 space mole We space have comma space 0.8 minus 0.5 equals space 0.3 space mole space of space CO subscript 2 1 space mole space of space CO subscript 2 minus negative negative negative negative negative negative negative greater than space 2 space moles space of space NaOH 0.3 space moles space of space CO subscript 2 minus negative negative negative negative negative negative negative negative negative greater than space 0.6 space moles space of space NaOH
Answered by Ravi | 27 Jul, 2021, 12:43: PM
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