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Asked by 22nd August 2008, 8:48 PM
Answered by Expert

Let A =x. Draw a perpendicular OD on BC. It can easily be shown that triangles OBD and ODC are congurent. So

BOD=  DOC =(2 x)/2=x ( Angle subtented at centre by an arc is double the correspomding angle subtended at segment)

So we have in triangle BOD,

cosx=BD/OB=BD/5... 1

Also triangles BAD and CAD are congurent.So   BAD=x/2

In triangle BAD,

cos x/2=BD/6...2

Using 1 and 2 we can calculate the values of BD.Consequently,BC=2BD


Answered by Expert 15th December 2008, 2:19 AM
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