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An integer is chosen at random from 1 to 200. What is the probability that the integer chosen is divisible by 6 or 8?

Asked by Topperlearning User 4th April 2014, 10:59 AM

Multiples of 6 are 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 168, 174, 180, 186, 192, 198.

Thus, no. of multiples of 6 = 33

Multiples of 8 are 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200.

Thus, no. of multiples of 8 = 25

Now, number of multiples of 6 and 8 are 24, 48, 72, 96, 120, 144, 168, 192

Thus, no. of multiples of 6 and 8 = 8

Now, number of multiples of 6 or 8 = 33 + 25 - 8 = 50

P (chosen integer is a multiple of 6 or 8) =

Answered by Expert 4th April 2014, 12:59 PM
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