NEET Class neet Answered
an ideal gas kept in open container at initial temperature 60 degree centigrate . when it is heated to T temperature 1/4th of gas is kept out of container , find out the value of T.
Asked by musira29rahman | 12 Oct, 2019, 03:28: PM
Expert Answer
For ideal gas, we have , pV = nRT
where p is pressure, V is volume of container, n is number of moles, R is gas constant and T is absolute temperature
Let at T = 60°C = 333 K , we have n moles present in container.
when it is heated 1/4 th of gas has been driven out means, only 3/4 th of n moles are in the container.
Since volume of cotainer is constant , to keep the same pressure, we have
n R Ti = (3/4) n R Tf or Tf = (4/3)Ti
where Ti is initial temperature and Tf is final temperature,
Hence final temperature = (4/3) × 333 = 444 K = 171 °C
Answered by Thiyagarajan K | 12 Oct, 2019, 10:24: PM
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